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Figure 1

P/N

LIFE(N)

1/(2N*50%)

1/(2N*30%)

1/(2N*20%)

1/MTBF=C+D+E

MTBF =1/(C+D+E)

81531651-01

20000

0.00005

8.33333E-05

0.000125

0.000258333

3870.967742

81575857

50000

0.00002

3.33333E-05

0.00005

0.000103333

9677.419355

81571877

20333

4.91811E-05

8.19686E-05

0.000122953

0.000254103

3935.419355

81530208

27000

3.7037E-05

6.17284E-05

9.25926E-05

0.000191358

5225.806452

81535421

50000

0.00002

3.33333E-05

0.00005

0.000103333

9677.419355

81571862-01

30000

3.33333E-05

5.55556E-05

8.33333E-05

0.000172222

5806.451613

81571867-01

24333

4.10965E-05

6.84941E-05

0.000102741

0.000212332

4709.612903

81537853-01

28000

3.57143E-05

5.95238E-05

8.92857E-05

0.000184524

5419.354839

81535301-01

38000

2.63158E-05

4.38596E-05

6.57895E-05

0.000162281

6162.162162

81531506-01

33700

2.96736E-05

4.9456E-05

7.4184E-05

0.000153314

6522.580645

81571568-01

21842

4.57834E-05

7.63056E-05

0.000114458

0.000236547

4227.483871

81571303-01

21750

4.5977E-05

7.66284E-05

0.000114943

0.000237548

4209.677419

81571654-01

58960

1.69607E-05

2.82678E-05

4.24016E-05

8.763E-05

11411.6129

81571568-01

21842

4.57834E-05

7.63056E-05

0.000114458

0.000236547

4227.483871

BOLTS

65000

1.53846E-05

2.5641E-05

3.84615E-05

7.94872E-05

12580.64516

LET FD=50%, AD=30%, ED=20%

THEN 1/MTBF= 1/(2N*50%) + 1/(2N*30%) +1/ (2N *20%), WHERE N= FATIGUE TEST LIFE.

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